Help me please one left!?

Draw it, so you have 2 equal lines seperated by a 126 degree angle.

If you now mirror these lines, you will get a parallogram (a rhombus).

Now draw a line from the tree (crossing of the first 2 lines) with the mirrored tree (crossing of the mirrored 2 lines). This line is your resultant force.

If you don't get this, just begin to draw and you'll see.

There are multiple ways to calculate the resultant force, but try this one:

use pythagoras, a^2+b^2=c^2 so

half resultant force ^2 + b^2 = F^2

and for b -> sin(63) (->half 126) = b/half resultant force

so b = sin(63) * half resultant force

Plug in:

half resultant force ^2 + (sin(63)*half resultant force)^2 = F^2

Now solve for half resultant force, and multiple by 2 (= resultant force)

Is about 1.5 times the seperate pulling force F